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5x^2-25x+15=-5
We move all terms to the left:
5x^2-25x+15-(-5)=0
We add all the numbers together, and all the variables
5x^2-25x+20=0
a = 5; b = -25; c = +20;
Δ = b2-4ac
Δ = -252-4·5·20
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-15}{2*5}=\frac{10}{10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+15}{2*5}=\frac{40}{10} =4 $
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